SOLUTION: Suppose that the length of a certain rectangle is 9 meters less than four times its width. The perimeter of the rectangle is 62 meters. Find the length and width of the rectangle.

Algebra ->  Graphs -> SOLUTION: Suppose that the length of a certain rectangle is 9 meters less than four times its width. The perimeter of the rectangle is 62 meters. Find the length and width of the rectangle.      Log On


   

Question 1011467: Suppose that the length of a certain rectangle is 9 meters less than four times its width. The perimeter of the rectangle is 62 meters. Find the length and width of the rectangle.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x = width.
then 4x-9 = length
perimeter = 2 * length + 2 * width = 62
you get 2 * x + 2 * (4x-9) = 62
simplify to get 2x + 8x - 18 = 62
add 18 to both sides of this equation to get:
2x + 8x = 80
combine like terms to get:
10x = 80
divide both sides of this equation by 10 to get:
x = 8
when x = 8, 4x-9 = 32-9 = 23.
your length is 23 and your width is 8.
that's your solution.
to confirm:
2 * length + 2 * width = 62 leads to:
2*23 + 2*8 = 46 + 16 = 62
length = 4 * width - 9 leads to:
23 = 4 * 8 - 9 = 32 - 9 = 23.