SOLUTION: Find the mean, variance, and standard deviation of the probability distribution, Complete parts (a) and (b) using the probability distribution below. The number of overtime hou

Click here to see ALL problems on Probability-and-statistics

Question 1011231: Find the mean, variance, and standard deviation of the probability distribution,
Complete parts (a) and (b) using the probability distribution below.
The number of overtime hours worked in one week per employee overtime hours.
0 1 2 3 4 5 6
Probability 0.032 0.058 0.169 0.296 0.228 0.143 0.074
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website!
0*0.032=0
1*0.058=0.058
2*0.169=0.338
3*0.296=0.888
4*0.228=0.912
5*0.143=0.715
6*0.074=0.444
Sum is 3.355, and that is the mean in hours
variance is{ (x^2)*p(x)}-mu^2
0*0.032=0
1*0.058=0.058
4*0.169=0.676
9*0.296=2.664
16*0.228=3.648
25*0.143=3.575
36*0.074=2.664
Sum is 13.285. Subtact mu^2=11.256=2.029=variance in hours ^2
1.4244 is standard deviation in hours.