SOLUTION: 12 sin^2(theda) =9

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Question 1011164: 12 sin^2(theda) =9
Answer by ikleyn(52925) About Me  (Show Source):
You can put this solution on YOUR website!
.
12%2Asin%5E2%28theta%29 = 9.
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Divide both sides by 12. You will get

sin%5E2%28theta%29 = 3%2F4.

Take square roots from both sides. You will get

sin%28theta%29 = +/- sqrt%283%29%2F2.

sin%28theta%29 = sqrt%283%29%2F2  -----> theta = +/- pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . .   or   theta = 2pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . . 

sin%28theta%29 = -sqrt%283%29%2F2  -----> theta = -pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . .   or   theta = -2pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . . 

Answer. The solutions are

         theta = pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . .

         theta = 2pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . .

         theta = -pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . . 

         theta = -2pi%2F3 + 2%2Ak%2Api, k = 0, +/-1, +/-2, . . .