SOLUTION: A small square is cut out of a larger square. The side lengths of both squares, in centimetres, are whole numbers less than 25. The remaining area of the larger square is 57 squar

Algebra ->  Surface-area -> SOLUTION: A small square is cut out of a larger square. The side lengths of both squares, in centimetres, are whole numbers less than 25. The remaining area of the larger square is 57 squar      Log On


   



Question 1011123: A small square is cut out of a larger square.
The side lengths of both squares, in centimetres, are whole numbers less than 25. The remaining area of the larger square is 57 square cm.
What is the perimeter of the small square in centimetres?
Solution: 32 cm
Can you show the work please. Thank you!

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= side length of the smaller square, in cm,
y= side length of the larger square, in cm,
and x%3Cy , of course.
So,
x%5E2= area of the smaller square, in square cm;
y%5E2= original area of the larger square, in square cm, and
y%5E2-x%5E2= remaining area of the larger square, in square cm.
The problem tells us that y%5E2-x%5E2=57 ,
and that x and y are positive integers less than 25.
Algebra tells us that
y%5E2-x%5E2=57<-->%28y-x%29%28y%2Bx%29=57 .
Since x and y are positive integers less than 25 , with x%3Cy%7D%7D%2C%0D%0A%7B%7B%7By-x and y%2Bx are positive integers, and
y-x%3Cy%2Bx%3C25%2B25=50 .
What positive integers less than 5 could be y-x and y%2Bx ?
As 57 does not have too many factors, we can only write it as two products of positive integers:
57=1%2A57 and 57=3%2A19 .
Only one of thpose products has both factors less than 50 .
So, system%28y-x=3%2Cy%2Bx=19%29---->system%28x=8%2Cy=11%29 .
The perimeter of the small square in centimetres is
4%2Ax=4%2A8=highlight%2832%29 .