SOLUTION: The cost of a can of chicken C can be found by the forumula c = a*q/t, where a is the amount of chicken, q is the quality of the chicken, and t time it takes to prepare and ship th

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Question 1011106: The cost of a can of chicken C can be found by the forumula c = a*q/t, where a is the amount of chicken, q is the quality of the chicken, and t time it takes to prepare and ship the chicken.
1. How will the cost of a can of chicken change if the quality of the chicken increases?
2. Ms. Dyer and Mr. Nice are buying chicken for a party. Ms. Dyer is buying more chicken, while Mr. Nice is buying less chicken but with higher quality than Ms. Dyer. Who will spend more, explain?
3. Write a rule that give t as a function of C,a, and q
4. Write a rule that gives q as a function of a, t, and C

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!

1.
c = a*q/t
assume q increases by a factor of b.
c = a*q/t becomes c = a * q * b / t.
c will increase by a factor of b.
example:
a = 5, q = 1, t = 5
c = aq/t becomes 5*1/5 = 5
q now becomes 2
you get:
c = aq/t becomes 5*2/5 = 6/5 = 2
the quality went up by a factor of 2, the cost went up by a factor of 2.

2.
ms. dyer buys more chickens, so her factor goes up.
mr. nice buys less chickens with higher quality, so his price can go up or down depending on the factors involved.
example:
ms. dyer buys 2 times as many chickens.
her cost will be equal to 2 * what it was before.
mr. nice buys half as many chickens.
if he pays 2 times as much per chicken, then his price will be 1/2 * 2 = 1 * what it was before which is less than what ms. dyer paid.
if he pays 4 times as much per chicken, then his price will be 1/2 * 4 = 2 * what it was before which is the same as what ms. dyer paid.
if he pays 6 times as much per chicken, then his price will be 1/2 * 6 = 3 * what it was before which is more than what ms. dyer paid.
it all depends on the factors involved.
there's no way of telling unless you know what those factors are.

3.
c = aq/t
multiply both sides of this equation by t and divide both sides of this equation by c to get:
t = aq/c

4.
c = aq/t
multiply both sides of this equation by t and divide both sides of this equation by a to get:
ct/a = q which is the same as:
q = ct/a