SOLUTION: Three dozen eggs and five loaves of bread cost $6.90; four dozen eggs and two loaves of bread cost $5.70. Find the prices for a dozen eggs and for a loaf of bread

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Three dozen eggs and five loaves of bread cost $6.90; four dozen eggs and two loaves of bread cost $5.70. Find the prices for a dozen eggs and for a loaf of bread      Log On


   



Question 1011034: Three dozen eggs and five loaves of bread cost $6.90; four
dozen eggs and two loaves of bread cost $5.70. Find the
prices for a dozen eggs and for a loaf of bread

Found 2 solutions by stanbon, addingup:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Three dozen eggs and five loaves of bread cost $6.90;
four dozen eggs and two loaves of bread cost $5.70.
Find the prices for a dozen eggs and for a loaf of bread
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3e + 5v = 690 cents
4e + 2v = 570 cents
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Modify for elimination::
12e + 20v = 4*690
12e + 6v = 3*570
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Subtract and solve for "v"::
14v = 1050
loaf price = 1050/14 = 75 cents
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Solve for "e"
4e + 2v = 570
4e + 150 = 570
4e = 420
eggs price = 105 cents
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Cheers,
Stan H.
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Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
eggs: x
bread: y
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3x+5y= 6.90 Multiply both sides times 2
4x+2y= 5.70 Multiply both sides times 5 and subtract from above:
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6x+10y= 13.80
-
20x+10y= 28.50
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-14x = -14.70 divide both sides by -14
x = 1.05 And now let's find y:
3(1.05)+5y= 6.90
3.15+5y= 6.90 subtract 3.15 from both sides
5y= 3.75 divide both sides by 5
y= 0.75
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Check:
3x+5y= 6.90; 3(1.05)+5(0.75)= 6.90. We have the correct answer.
Now let's see if we can prove the other equation to be true as well:
4x+2y= 5.70; 4(1.05)+2(0.75)= 5.70. Again we have the correct answer.
A dozen eggs is $1.05 and a loaf of bread $0.75