SOLUTION: Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 .5 hours one bus reached town B, while th

Algebra ->  Finance -> SOLUTION: Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 .5 hours one bus reached town B, while th      Log On


   

Question 1011027: Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 .5 hours one bus reached town B, while the other bus was away from town B at a distance equal 1/ 6 of the distance between A and B. Find the speed of the buses and the distance between A and B.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I'll give it a shot, but it's a
little hard to follow
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Let +s+ = the speed of the slower bus in mi/hr
+s+%2B+10+ = the speed of the faster bus in mi/hr
Let +d+ = the distance between the towns in miles
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Equation for the faster bus:
(1) +d+=+%28+s+%2B+10+%29%2A3.5+
Equation for the slower bus:
(2) +%281%2F6%29%2Ad+=+s%2A3.5+
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(1) +d+=+3.5s+%2B+35+
and
(2) +d+=+21s+
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+21s+=+3.5s+%2B+35+
+17.5s+=+35+
+s+=+2+
+s+%2B+10+=+12+
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(2) +d+=+21s+
(2) +d+=+21%2A2+
(2) +d+=+42+
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The speed of the slower bus was 2 mi/hr
The speed of the faster bus was 12 mi/hr
The distance between A and B was 42 mi
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check:
(1) +d+=+%28+s+%2B+10+%29%2A3.5+
(1) +d+=+%28+2+%2B+10+%29%2A3.5+
(1) +d+=+42+
OK
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These numbers are a little strange -check my math