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One number is 5 more than another. The difference between their squares is 105. What are the numbers?
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Let x be the greater number, and let y be the smaller one.
Then we have two equations from the condition
x - y = 5, (1)
and
=
. (2)
Factor (2):
(x-y)*(x+y) = 105. (3)
Replace the first factor in (3) by 5, in accordance with (1). You will get
5*(x+y) = 105, hence
x + y =
= 21. (4)
Thus you have the system of two equations (1) and (4):
x - y = 5, (1') and
x + y = 21. (4')
Add (1') and (4'). You will get 2x = 26. Hence, x = 13.
Distract (1') from ((4'). You will get 2y = 16. Hence, y = 8.
Answer. x = 13, y = 8.