SOLUTION: Factorise fully 6k+12k^2-3k^3
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Question 1010885
:
Factorise fully 6k+12k^2-3k^3
Answer by
fractalier(6550)
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6k + 12k^2 - 3k^3 =
3k(2 + 4k - k^2) = -3k(k^2 - 4k - 2)