SOLUTION: when chris drives his car to work the trip takes 1/2hr when he rides the bus it takes 3/4hr the average rate of driving is 12mph more than his rate when riding the bus. Find the di
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-> SOLUTION: when chris drives his car to work the trip takes 1/2hr when he rides the bus it takes 3/4hr the average rate of driving is 12mph more than his rate when riding the bus. Find the di
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Question 1010852: when chris drives his car to work the trip takes 1/2hr when he rides the bus it takes 3/4hr the average rate of driving is 12mph more than his rate when riding the bus. Find the distance he travels to work (note:Driving distance=Distance on bus) Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! we have two (rate * time = distance) equations
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let r be the rate for the bus
r * (0.75) = distance
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r + 12 is the rate for the car
(r+12) * (0.50) = distance
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now set the two equations equal to each other since the car and the bus cover the same distance
0.75r = 0.50r + 6
0.25r = 6
r = 24 mph
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you can use either equation to find the distance traveled
24 * (0.75) = 18 miles
