SOLUTION: log3(2x+7)=4
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Question 1010818
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log3(2x+7)=4
Answer by
lwsshak3(11628)
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log3(2x+7)=4
convert to exponential form: base(3) raised to log of number(3)=number(2x+7)
3^4=2x+7
3^4=2x+7
2x=3^4-7=81-7=74
x=37