SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 83/mi h faster than the other. If the two jets are 9864 mi apart after 8 hours, wha

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Question 1010669:
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 83/mi h faster than the other. If the two jets are 9864 mi apart after 8 hours, what is the rate of each jet?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the speed of the slower jet in mi/hr
+s+%2B+83+ = the speed of the faster jet in mi/hr
---------------------
You can think of this as one of the jets ( either one )
standing still and the other one traveling away
from it at the sum of their speeds
---------------------
+9864+=+%28+s+%2B+s+%2B+83+%29%2A8+
+9864+=+16s+%2B+664+
+16s+=+9200+
+s+=+575+
and
+s+%2B+83+=+658+
The jet's speeds are 575 mi/hr and 658 mi/hr
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check:
+d%5B1%5D+=+s%2A8+
+d%5B1%5D+=+575%2A8+
+d%5B1%5D+=+4600+
and
+d%5B2%5D+=+%28+s+%2B+83+%29%2A8+
+d%5B2%5D+=+658%2A8+
+d%5B2%5D+=+5264+
and
+d%5B1%5D+%2B+d%5B2%5D+=+4600+%2B+5264+
+d%5B1%5D+%2B+d%5B2%5D+=+9864+
OK