SOLUTION: the Yankee Clipper leaves the pier at 9:00 am at 8 nautical miles per hour. A half hour later, the River Rover leaves the same pier in the same direction traveling at 10 nautical

Algebra ->  Expressions-with-variables -> SOLUTION: the Yankee Clipper leaves the pier at 9:00 am at 8 nautical miles per hour. A half hour later, the River Rover leaves the same pier in the same direction traveling at 10 nautical       Log On


   



Question 101048This question is from textbook Glenco Algebra 1
: the Yankee Clipper leaves the pier at 9:00 am at 8 nautical miles per hour. A half hour later, the River Rover leaves the same pier in the same direction traveling at 10 nautical miles per hour. At what time will the River Rover overtake the Yankee Clipper. I know it has to do with the d=r/t formula but I have no idea how to set it up. Could you please help. This question is from textbook Glenco Algebra 1

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the YC has a 4nm head start (8nmph*.5hr)

the difference in speed is 2nmph (10nmph-8nmph)

so it takes RR 2hr (4nm/2nmph) to catch YC ... this is 2 hr after RR's 9:30 departure

equation wise; they will meet when they have traveled the same distance, so rt=rt

8(t)=10(t-.5) ... RR's rate is faster and time is shorter ... the t in this equation is YC's time