Question 1010453: There is an initiation fee to join the Wellness Center, as well as monthly dues. The total cost after 7 months' membership will be $335, and after 1 1/2 year, $830. Find both the initiation fee and the monthly dues. Setup a system of equations and solve. Label your answers. Show step by step.
Thanks in advance!
Found 3 solutions by Cromlix, josmiceli, stanbon: Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
The total cost after 7 months' membership will be $335
Make initiation fee = x
Make monthly due = y
x + 7y = $335
and after 1 1/2 year, $830.
x + 18y = $830
..............
x + 7y = $335.......(1)
x + 18y = $830......(2)
Subtract (1) from(2)
....11y = $495
....y = $45
Substitute y = $45 in (1)
x + 7y = $335
x + 7($45) = $335
x + $315 = $335
x = $335 - $315
x = $20
Initiation fee = $20
Monthly due = $45
Hope this helps :-)
Answer by josmiceli(19441) (Show Source): Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! There is an initiation fee to join the Wellness Center, as well as monthly dues. The total cost after 7 months' membership will be $335, and after 1 1/2 year, $830. Find both the initiation fee and the monthly dues. Setup a system of equations and solve. Label your answers. Show step by step.
Equations:
f + (7/12)d = 335
f + (3/2)d = 830
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Subtract and solve for "d":
[(3/2)-(7/12)]d = 495
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[(36-14)/24]d = 495
(11/12)d = 495
(1/12)d = 45
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dues = 12*45 = $540
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Solve for "f":
f + (3/2)d = 830
f = 830-(3/2)540
fee = 830-818 = $12
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Cheers,
Stan H.
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