SOLUTION: Five times of a positive integer less than twice its square by 3.Find the integer. solve this sums

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Question 1010428: Five times of a positive integer less than twice its square by 3.Find the integer. solve this sums
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
I think you mean
2x^2 - 5x = 3
2x^2 - 5x - 3 = 0
(2x + 1)(x - 3) = 0
x = -1/2 and x = 3
Since it is a positive you want,
x = 3