SOLUTION: A bicyclist accelerates uniformly from a speed of 2.50 m/s forward to 5.55 m/s forward at a rate of +0.525 m/s^2. How far did the bicyclist move during this acceleration?
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Question 1010420: A bicyclist accelerates uniformly from a speed of 2.50 m/s forward to 5.55 m/s forward at a rate of +0.525 m/s^2. How far did the bicyclist move during this acceleration? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A bicyclist accelerates uniformly from a speed of 2.50 m/s forward to 5.55 m/s forward at a rate of +0.525 m/s^2. How far did the bicyclist move during this acceleration?
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Change in speed = 5.55-2.50 = 3.05 m/sec
t = 3.05/0.525 =~ 5.8095 seconds
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Average speed = (2.5+5.55)/2 = 4.025 m/sec
distance = avg speed*t
d = 23.38333 meters
