SOLUTION: How do I solve {{{x^2-3x-10=0}}} by factoring?

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Question 1010238: How do I solve x%5E2-3x-10=0 by factoring?
Found 2 solutions by fractalier, rothauserc:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
We factor
x%5E2-3x-10=0
into binomial factors, looking for two numbers that multiply to make ten but have a difference of 3...5 and 2 are the numbers...since the middle term is -3, we know that our factoring has to have -5, like this...
%28x+-+5%29%28x+%2B+2%29+=+0
Then
x = 5 or x = -2

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 -3x - 10 = 0
look at prime factors of 10 which are 2 and 5, therefore
x^2 - 3x - 10 = (x - 5) * (x + 2)