SOLUTION: The Distance it takes a car to stop varies directly as the square of the speed of the car. If it takes 125 feet for a car traveling 50 miles per hour to stop, what distance is requ
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-> SOLUTION: The Distance it takes a car to stop varies directly as the square of the speed of the car. If it takes 125 feet for a car traveling 50 miles per hour to stop, what distance is requ
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Question 1010219: The Distance it takes a car to stop varies directly as the square of the speed of the car. If it takes 125 feet for a car traveling 50 miles per hour to stop, what distance is required for a speed of 44 miles per hour?
(round to the nearest hundredth if necessary) Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! We write this relationship as
d = kv^2
Now plugging in we get
125 feet = k(55 mph)^2
125 = 3025k
k = .04132
Then we find d using our new value of k...
d = (.04132)(44^2) = 80 feet
