SOLUTION: To the nearest tenth of an inch, find the length of a diagonal of a square whose side length is 8 inches.

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Question 1010143: To the nearest tenth of an inch, find the length of a diagonal of a square whose side length is 8 inches.
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Pythagoras:
a^2+b^2= c^2
8^2+8^2= hypotenuse^2
64+64= h^2
128= h^2 take the square root of both sides
h= 11.3 is the hypotenuse, which is the diagonal in your square