SOLUTION: I am having trouble with this proble,. It is in a section of the textbook dealing with systems of equations with two variables. A fulcrum is placed so that weights of 60 pounds

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Question 101013This question is from textbook Intermediate Algebra
: I am having trouble with this proble,. It is in a section of the textbook dealing with systems of equations with two variables.
A fulcrum is placed so that weights of 60 pounds and 100 pounds are in balance. If 20 pounds is subtracted from the 100 pound weight, then the 60 pound weight must be moved 1 foot closer to the fulcrum to preserve the balance. Find the original distance between the 60 pound and 100 pound weights. This question is from textbook Intermediate Algebra

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=distance ... 60x=100y

60(x-1)=80y ... 60x-60=80y ... 60x=80y+60

100y=80y+60 ... 20y=60 ... y=3

60x=100(3) ... 60x=300 ... x=5

x+y=8