Question 1009827: find the largest number of four digit divisible by 12 15 18 27 ? Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52802) (Show Source):
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Find the largest number of four digits divisible by 12 15 18 27 ?
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The least common multiple of these numbers is = 4*27*5 = 540.
So, the question is: what is the largest number of four digits divisible by 540?
It is the whole part of the number = 18.517 multiplied by 540, i.e 18*540 = 9720.
