SOLUTION: How do I graph the solution of the system of linear inequalities x<4y+2 x+y<0

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Question 1009750: How do I graph the solution of the system of linear inequalities
x<4y+2
x+y<0

Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Both exclusive inequalities, the related lines are not part of the solution set.

System is system%28y%3Ex%2F4-1%2F2%2Cy%3C-x%29.
Shade the region for each and accentuate the region in common to both.

graph%28300%2C300%2C-4%2C4%2C-4%2C4%2Cy%3Ex%2F4-1%2F2%2Cy%3C-x%29
THIS GRAPH IS BAD BECAUSE TOO MUCH IS SHADED. There is a region at the left that needs to be shaded but too much above and below is also shown shaded which should not be.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x%3C4y%2B2
y%3E+x%2F4-1%2F2.......eq.1
x%2By%3C0...........eq.2
---------------
find intersection point, do it as you have equal sign
x%2By=0=>y=-x...substitute in
x=4y%2B2=>x=4%28-x%29%2B2=>x=-4x%2B2=>x%2B4y=2=>5x=2=>x=2%2F5
then y=-x=>y=-2%2F5
so, intersection point is at: (2%2F5,-2%2F5)