SOLUTION: One number is six less than a first number. A third number is twice the first number. If the sum of the three numbers is 306, find the numbers.
Question 100974This question is from textbook Intermediate Algebra
: One number is six less than a first number. A third number is twice the first number. If the sum of the three numbers is 306, find the numbers. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! Lets call the first number x
Now define the other numbers in terms of x
Given: one number is six less than a first number
second number = x-6
Given: a third number is twice the first number
third number = 2x
Given: the sum of the three numbers is 306
Now we can write an equation to solve for x (first number)
(first#)+(second#)+(third#) = 306
(x) + (x-6) + (2x) = 306
x + x - 6 + 2x = 306
4x - 6 = 306
4x = 312
x = 78 Answer: first number is 78
now we can find the other numbers
second number = x - 6
second number = 78 - 6
second number = 72 Answer: second number is 72
third number = 2x
third number = 2(78)
third number = 156 Answer: third number is 156
Check answers:
(first#)+(second#)+(third#) = 306
78 + 72 + 156 = 306
306 =306
