SOLUTION: The length of a rectangle exceeds its width by 5m. If the width is increased by 1m and the length is decreased by 2m, the area of the new rectangle is 4 sq m less than the area of
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-> SOLUTION: The length of a rectangle exceeds its width by 5m. If the width is increased by 1m and the length is decreased by 2m, the area of the new rectangle is 4 sq m less than the area of
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Question 1009726: The length of a rectangle exceeds its width by 5m. If the width is increased by 1m and the length is decreased by 2m, the area of the new rectangle is 4 sq m less than the area of the original rectangle. Find the dimensions of the original rectangle. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! The area is A = LW for a rectangle.
We have originally
L = W + 5
Then the area is (W+5)W = W^2 + 5W
Then
(L-2)(W+1) = W^2 + 5W - 4
Substituting we get
(W+5 - 2)(W+1) = W^2 + 5W - 4
(W + 3)(W + 1) = W^2 + 5W - 4
W^2 + 4W + 3 = W^2 + 5W - 4
and W = 7 m so that
L = 12 m
