SOLUTION: Write the slope-intercept form of the equation with the given characteristics. 1. slope=1/4 ; y-intercept=2 2. slope=-3/2 ; passes through (-4,7) 3. passes throug

Algebra ->  Linear-equations -> SOLUTION: Write the slope-intercept form of the equation with the given characteristics. 1. slope=1/4 ; y-intercept=2 2. slope=-3/2 ; passes through (-4,7) 3. passes throug      Log On


   



Question 1009627: Write the slope-intercept form of the equation with the given characteristics.

1. slope=1/4 ; y-intercept=2

2. slope=-3/2 ; passes through (-4,7)

3. passes through (-2,1) and (2,-5)

4. parallel to the line y=-3x+5 ; passes through (-4,5)

8. perpendicular to the line y=1/2x-8 ; passes through (7,-6)

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Basic understanding should be, the form is y=mx+b, and m is slope, and a point on the line, actually on the y-axis is (0,b). The formula can be solved for b, giving b=y-mx.


ONLY two of the questions you asked will be solved here.

#8
For perpendicular, you want negative reciprocal of 1%2F2 for the slope, which is -2. Find the y-intercept using b=y-mx=-6-%28-2%29%2A7=8;
the resulting equation then being highlight%28y=-2x%2B8%29.

With that one, you should know how to do #2 yourself.

#3
m=%28-5-1%29%2F%282-%28-2%29%29=-6%2F4=-3%2F2
So far giving y=-%283%2F2%29x%2Bb and you can find b;
pick either point of the line, maybe (-2,1);
b=1-%28-3%2F2%29%2A%28-2%29
b=1-%283%2F2%292
b=1-3
b=-2
The equation being looked for is highlight%28y=-%283%2F2%29x-2%29.