SOLUTION: twice one number is 15 less than a second number. when 13 is added to the second number, the result is 7 less than 9 times the first number. find the numbers.
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: twice one number is 15 less than a second number. when 13 is added to the second number, the result is 7 less than 9 times the first number. find the numbers.
Log On
Question 1009617: twice one number is 15 less than a second number. when 13 is added to the second number, the result is 7 less than 9 times the first number. find the numbers. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
F=first number; S=second number
.
2F+15=S
.
S+13=9F-7
(2F+15)+13=9F-7
2F+35=9F
35=7F
5=F
ANSWER 1: The first number is 5.
.
S=2F+15=2(5)+15=10+15=25
ANSWER 2: The second number is 25.
.
CHECK:
S+13=9F-7
25+13=9(5)-7
38=45-7
38=38