SOLUTION: solve for f I know the equation is c=5/9(f-32) and I know the answer is f=32+9c/5 my problem is i don't understand how to write it using f=(___)c+___ if fractions are required ent

Algebra ->  Expressions-with-variables -> SOLUTION: solve for f I know the equation is c=5/9(f-32) and I know the answer is f=32+9c/5 my problem is i don't understand how to write it using f=(___)c+___ if fractions are required ent      Log On


   

Question 1009608: solve for f I know the equation is c=5/9(f-32) and I know the answer is f=32+9c/5 my problem is i don't understand how to write it using f=(___)c+___ if fractions are required enter them as improper fractions
Found 2 solutions by macston, josgarithmetic:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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C=%285%2F9%29%28F-32%29 . Multiply each side by 9/5.
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%289%2F5%29C=F-32 . Add 32 to each side.
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%289%2F5%29C%2B32=F

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The numbers appear to be temperature conversion between Fahrenheit and Celsius. Properties of Numbers will give you what you are looking for. F is composed of two terms. Commutative Property of Addition and of Multiplication are what you can use.

F=32%2B9c%2F5
9c%2F5%2B32
9%281%2F5%29c%2B32
%289%2F5%29c%2B32