SOLUTION: Write an equation of a sine function with the given amplitude=3 period=2pi/3 and phase shift pi/6

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Question 1009347: Write an equation of a sine function with the given amplitude=3 period=2pi/3 and phase shift pi/6
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation of a sine function with the given
amplitude=3 ; period=2pi/3 ; and phase shift pi/6
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Form:: y = a*sin(b(x-c))+d
amp = a = 3
period = (2pi)/b = (2pi/3)
phase shift = c/a = pi/6
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a = 3
b = 3
c = (3/6)pi = (pi/2)
d = 0
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Ans: y = 3*sin(3(x-(pi/2)) OR y = 3sin(3x-(3/2)pi)
Cheers,
Stan H.
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