SOLUTION: how much 50% antifreeze solution and 40% antifreeze solution should be mixed to obtain 50 gallons of 47% antifreeze solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how much 50% antifreeze solution and 40% antifreeze solution should be mixed to obtain 50 gallons of 47% antifreeze solution      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1009305: how much 50% antifreeze solution and 40% antifreeze solution should be mixed to obtain 50 gallons of 47% antifreeze solution
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the amount of 50% solutioin.
Thus 50-x will be the amount of 40% solution.
The set up is then
.50x + .40(50-x) = .47(50)
.50x + 20 - .40x = 23.5
.10x = 3.5
x = 35 gallons of 50% solution
50-x = 15 gallons of 40% solution