SOLUTION: Neena drew a rectangle with an area of 108 square millimeters. Its length was three times as long as its width. What was the length and width of Neena's rectangle?

Algebra ->  Linear-equations -> SOLUTION: Neena drew a rectangle with an area of 108 square millimeters. Its length was three times as long as its width. What was the length and width of Neena's rectangle?      Log On


   



Question 100904: Neena drew a rectangle with an area of 108 square millimeters. Its length was three times as long as its width. What was the length and width of Neena's rectangle?
Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
Lets call the width x
Now define the length in terms of x
Given: the length is three times as long as the width
length = 3x
Given: area of rectangle is 108 square millimeters
Now since we know that the area of a rectangle equals length times width
we can write a formula to solve for x
(length)(width) = area
%283x%29%28x%29=108 multiply terms
3x%5E2=108 divide both sides by 3
x%5E2=36 take square root of both sides
x=6
Answer: width is 6 millimeters
Next we can find the length
length = 3x
length = 3(6)
length = 18
Answer: length is 18 millimeters
Check answers with the formula for area
length times width = area
(18)(6)=108
108=108