SOLUTION: convert 8-8i into polar form with argument θ between 0 and 2π

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Question 1008991: convert 8-8i into polar form with argument θ between 0 and 2π
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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8 - 8i = 8*(1-i).

1 - i has a polar angle theta = 2pi+-+pi%2F4 = 7pi%2F4 and the modulus of sqrt%282%29.

Therefore, 8-8i = 8%2Asqrt%282%29%2A%28cos%287pi%2F4%29+%2B+i%2Asin%287pi%2F4%29%29.