SOLUTION: The length of a lacrosse field is 10yd less than twice its width, and the perimeter is 340yd. The defensive area is 7/22 of the total field. Find the defensive area of the lacrosse

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Question 1008905: The length of a lacrosse field is 10yd less than twice its width, and the perimeter is 340yd. The defensive area is 7/22 of the total field. Find the defensive area of the lacrosse field
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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W=width; L=length=2W-10yds; P=perimeter
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P=2(L+W)
340yds=2((2W-10yds)+W)
170yds=3W-10yds
180yds=3W
60yds=W
L=2W-10yds=2(60yds)-10yds=110yds
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Total Area=LW=(110yds)(60yds)=6600 sq yds
Defensive area=(7/22)(6600 sq yds)=2100 sq yds
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ANSWER: The defensive area is 2100 square yards.