SOLUTION: Two planes, which are 3650 miles apart, fly toward each other. Their speeds differ by 80 mph. If they pass each other in 5 hours, what is the speed of each?

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Question 1008765: Two planes, which are
3650 miles apart, fly toward each other. Their speeds differ by 80 mph. If they pass each other in 5 hours, what is the speed of each?

Found 2 solutions by stanbon, addingup:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Two planes, which are
3650 miles apart, fly toward each other. Their speeds differ by 80 mph. If they pass each other in 5 hours, what is the speed of each?
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1st plane speed:: x mph
2nd plane speed:: x+80 mph
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Combined speed:: 2x+80 mph
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Equation:
distance/time = speed
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3650/5 = 2x+80
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3650 = 10x+400
10x = 3250
x = 325 mph
x+80 = 405 mph
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Cheers,
Stan H.
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Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website!
Distance = rate*time (rate is another word for speed)
Divide both sides by time:
rate= distance/time
The rate is x for one plane and x-80 for the other:
3650/5 = x+x-80
730= x+x-80
730 = 2x-80 add 80 on both sides
810 = 2x Divide both sides by 2:
x= 810/2= 405 is the speed of one plane, and the other:
405 - 80= 325
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Check:
405*5 + 325*5= 3650
2025 + 1625= 3650
3650 = 3650 We have the correct answer