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Question 1008719: serigo, jim, simone, maria and dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) in how many ways can they arrive?
b) in how many ways can sergio arrive first and dawn last?
c) find the probability that sergio will arrive first and dawn last?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! serigo, jim, simone, maria and dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) in how many ways can they arrive?:: 5!
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b) in how many ways can sergio arrive first and dawn last?::1*1*3!
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c) find the probability that sergio will arrive first and dawn last?
# of ways to succeed:: 3! = 6
# of possible arrangements:: 5!
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Ans: 6/5! = 0.05
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Cheers,
Stan H.
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