Question 1008696: One number is 3 more than another. The difference between their squares is 51. What are the numbers? Found 2 solutions by stanbon, fractalier:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! One number is 3 more than another. The difference between their squares is 51. What are the numbers?
------
Equations:
x = y + 3
x^2 - y^2 = 51
-------
Substitute for "x" and solve for "y"::
(y+3)^2 - y^2 = 51
-------
y^2+6y+9 - y^2 = 51
6y+9 = 51
6y = 60
y = 10
-----
solve for "x"::
x = y + 3
x = 13
------------
Cheers,
Stan H.
----------
You can put this solution on YOUR website! Call the numbers x and y. Thus we have
x = y + 3 and
x^2 - y^2 = 51
Now substitute and get
(y+3)^2 - y^2 = 51
y^2 + 6y + 9 - y^2 = 51
6y + 9 = 51
6y = 42
y = 7
x = 10
(