SOLUTION: The sum of the digits of a three-digit number is 11. The tens digit is three times the Hundreds digit and twice the units digit. Find the original number. Help! I don't really k

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Question 1008650: The sum of the digits of a three-digit number is 11. The tens digit is three times the Hundreds digit and twice the units digit. Find the original number.
Help! I don't really know on how to do this.. ._.
Answer by maxitee(11) About Me  (Show Source):
You can put this solution on YOUR website!
Let's take the digits in the number to be A B and C.
From the question,
A + B + C = 11
A=> Hundreds,
B=> Tens
C= Units.
B = 3A ( tens digit is three times the hundreds digit.. As in the question)
B = 2C (tens digit is twice the unit digit.. As in the question)
This therefore means that 3A = 2C = B.
To relate all elements together, we have.
C = 3A/2
A= 2C/3
B= 3A or B = 2C.
From the first equation, (A+B+C=11)
If we substitute the values of B and C in terms of A, we have the following;
A+%2B+3A+%2B+3A%2F2+=+11

4A%2B3A%2F2+=+11

11A%2F2+=11
11A+=+22
A+=+2
If A = 2, Then B = 6, Making C = 3.
The original number is 263

(Engr. Terry, Nigeria)