SOLUTION: Find three consecutive natural numbers if the square of the smallest number is 65 less than the product of the remaining two numbers.
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Question 1008541: Find three consecutive natural numbers if the square of the smallest number is 65 less than the product of the remaining two numbers. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find three consecutive natural numbers if the square of the smallest number is 65 less than the product of the remaining two numbers.
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1st:: x-1
2nd:: x
3rd:: x+1
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Equation:
(x-1)^2 = x(x+1)-65
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x^2 - 2x + 1 = x^2 + x - 65
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3x = 66
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x = 22
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x-1 = 21
x = 22
x+1 = 23
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Cheers,
Stan H.
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