SOLUTION: Mike has $28.05 in dimes and quarters. The number of dimes is 3 times the number of quarters. Write a system of linear equations to find how many dimes and quarters there are.
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Question 1008505: Mike has $28.05 in dimes and quarters. The number of dimes is 3 times the number of quarters. Write a system of linear equations to find how many dimes and quarters there are. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
D=dimes=3Q; Q=quarters
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$0.10D+$0.25Q=$28.05
$0.10(3Q)+$0.25Q=$28.05
$0.30Q+$0.25Q=$28.05
$0.55Q=$28.05
Q=51
ANSWER 1: Mike has 51 quarters.
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D=3Q=3(51)=153
ANSWER 2: Mike has 153 dimes.
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CHECK:
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$0.10D+$0.25Q=$28.05
$0.10(153)+$0.25(51)=$28.05
$15.30+$12.75=$28.05
$28.05=$28.05
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