SOLUTION: Given a line with equation . Write an equation in point-slope form of the line perpendicular to the given line through the point (2, -3).

Algebra ->  Linear-equations -> SOLUTION: Given a line with equation . Write an equation in point-slope form of the line perpendicular to the given line through the point (2, -3).       Log On


   

Question 1008437: Given a line with equation . Write an equation in point-slope form of the line perpendicular to the given line through the point (2, -3).
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Given a line with equation ____ ???.
The problem is broken, because we did not get the equation,
so I will fix it by making up an equation.
I will assume that your equation has an x AND a y .
If there is an x AND a y , your line has a slope, and so does the perpendicular line.
I will use equation y=-2x%2B3 ,
which is given in slope-intercept form y=mx%2Bb
The slope of that line is m=-2 and the y-intercept is b=3 .
The slope of a perpendicular line is m%5Bperp%5D=%28-1%29%2Fm=%28-1%29%2F%28-2%29=1%2F2
A line with slope m passing through point P%28x%5BP%5D%2Cy%5BP%5D%29
can be written in point-slope form as
y-y%5BP%5D=m%28x-x%5BP%5D%29 .
For the perpendicular line in the answer to the problem as I fixed it,
the slope is m=1%2F2 and the point is P%282%2C+-3%29 withsystem%28x%5BP%5D=2%2Cy%5BP%5D=-3%29 , so the equation is
y-%28-3%29=%281%2F2%29%28x-2%29<-->highlight%28y%2B3=%281%2F2%29%28x-2%29%29 .