SOLUTION: A man has 20 coins in his pocket consisting of 5-peso,10-peso, and 1-peso coins. There are an equal number of ones and fives among them.He has 88 pesos in all. How many coins of e
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-> SOLUTION: A man has 20 coins in his pocket consisting of 5-peso,10-peso, and 1-peso coins. There are an equal number of ones and fives among them.He has 88 pesos in all. How many coins of e
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Question 1008373: A man has 20 coins in his pocket consisting of 5-peso,10-peso, and 1-peso coins. There are an equal number of ones and fives among them.He has 88 pesos in all. How many coins of each denomination are there? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
N=1 peso coins; F=5 peso coins=N T=10 peso coins
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N+F+T=20
N+N+T=20
T=20-2N
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(1)N+5(F)+10(T)=88
N+5(N)+10(20-2N)=88
6N+200-20N=88
-14N=-112
N=8
ANSWER 1: There are eight 1 peso coins.
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F=N=8
ANSWER 2: There are eight 5 peso coins.
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T=20-2N=20-2(8)=20-16=4
ANSWER 3: There are four 10 peso coins.
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CHECK:
1(N)+5(F)+10(T)=88
1(8)+5(8)+10(4)=88
8+40+40=88
88=88
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