SOLUTION: Write an equation in slope -intercept form for the line that contains the given point is parallel to the given line. (-3,1);y=-5x+2

Algebra ->  Linear-equations -> SOLUTION: Write an equation in slope -intercept form for the line that contains the given point is parallel to the given line. (-3,1);y=-5x+2      Log On


   

Question 100819: Write an equation in slope -intercept form for the line that contains the given point is parallel to the given line. (-3,1);y=-5x+2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is -5 (its from the slope of y=-5%2Ax%2B2 which is also -5). Also since the unknown line goes through (-3,1), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y-1=-5%2A%28x%2B3%29 Plug in m=-5, x%5B1%5D=-3, and y%5B1%5D=1



y-1=-5%2Ax%2B%285%29%28-3%29 Distribute -5



y-1=-5%2Ax-15 Multiply



y=-5%2Ax-15%2B1Add 1 to both sides to isolate y

y=-5%2Ax-14 Combine like terms

So the equation of the line that is parallel to y=-5%2Ax%2B2 and goes through (-3,1) is y=-5%2Ax-14


So here are the graphs of the equations y=-5%2Ax%2B2 and y=-5%2Ax-14



graph of the given equation y=-5%2Ax%2B2 (red) and graph of the line y=-5%2Ax-14(green) that is parallel to the given graph and goes through (-3,1)