SOLUTION: Circle with center at (7, -3) and tangent to the line y = 2.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Circle with center at (7, -3) and tangent to the line y = 2.      Log On


   

Question 1008152: Circle with center at (7, -3) and tangent to the line y = 2.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Circle with center at (7, -3) and tangent to the line y = 2.
----
radius = 2--3 = 5
----
Equation:
(x-7)^2 + (y+3)^2 = 5^2
---------------
Cheers,
Stan H.
-------------