Question 1008127: One positive integer is 4 less than twice another. The sum of their squares is 901. What are the two intergers. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! One positive integer is 4 less than twice another. The sum of their squares is 901. What are the two intergers.
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Equations:
y = 2x-4
y^2 + x^2 = 901
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Substitute for "y" and solve for "x"::
(2x-4)^2+x^2 = 901
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4x^2 - 16x + 16 + x^2 = 901
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5x^2 - 16x - 885 = 0
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x = 15
y = 31
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Cheers,
Stan H.
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