SOLUTION: the width of a rectangle is 4 inches greater than half the length the perimeter is 56 inches find the length and width of the rectangle give length then width seperated by a comma

Algebra ->  Rectangles -> SOLUTION: the width of a rectangle is 4 inches greater than half the length the perimeter is 56 inches find the length and width of the rectangle give length then width seperated by a comma      Log On


   

Question 1008110: the width of a rectangle is 4 inches greater than half the length the perimeter is 56 inches find the length and width of the rectangle give length then width seperated by a comma there is no equation
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the width of a rectangle is 4 inches greater than half the length
W = (1/2)L + 4
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the perimeter is 56 inches
2(L+W) = 56
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find the length and width of the rectangle give length then width seperated by a comma there is no equation
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Substitute for "W" and solve for "L"::
L + W = 28
L + (1/2)L + 4 = 28
(3/2)L = 24
(1/2)L = 8
L = 16 inches
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Solve for "W"
L + W = 28
W = 12 inches
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cheers,
Stan H.
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