Question 1008082: A college math class has 5 students with liberal arts majors, 8 students with business majors, 10 students with humanities majors, and 7 students with science majors.
a) The math teacher wants feedback about her class and will select 3 students at random with whom to talk. In how many ways can the students be selected so that at least 1 will be a science major?
b) The math teacher needs one of her students to turn in end of course surveys. If she selects the students at random, what is the probability that the student will be a business major?
c) What are the odds that the student chosen to turn in the end of course surveys will be a business major?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! If one is a science major, then the other is 23C2=253
There are 7 ways to choose 1 science major, so that number is 1771.
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If 2 are science majors, there are 7C2 or 21 ways to choose them and 23 ways to choose the rest, or 483,
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If all 3 are science majors, there are 7C3 or 35 ways to choose them
a. 2289
b. 8/30=4/15=0.267
c. Odds are prob yes/prob no
=8/30/22/30=8/22=4/11
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