Question 1007986: A plane travels at a speed of 190 mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 2 hours longer to complete the return trip. What was the wind velocity? (Round your answer to the nearest tenth.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A plane travels at a speed of 190 mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 2 hours longer to complete the return trip. What was the wind velocity? (Round your answer to the nearest tenth.)
------
With wind DATA:
rate = 190+w mph ; distance = 950 miles ; time = d/r = 950/(190+w) hrs
---
Against wind DATA:
rate = 190-w mph ; distance = 950 miles ; time = 950/(190-w) hrs
----
Equation:
against - with = 2 hrs
----
950/(190-w) - 950/(190+w) = 2
------
950(190+w) - 950(190-w) = 2(190^2-w^2)
----
2(950w) = 2(190^2-w^2)
----
w^2 + 950w - 190^2 = 0
-----
wind = 36.59 mph
----------
Cheers,
Stan H.
-------------------
|
|
|
