SOLUTION: A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find h
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Question 1007801: A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find his speed? Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website! where is distance, is speed, and is time
if a cyclist bikes at a constant speed for , we have ..............solve for .......eq.1
if he then returns home at the same speed but takes a different route, and his return trip takes longer and is , we have
.............solve for .........eq.2
eq.1 and eq.2 have equal left sides, so make equal right sides and solve for .......cross multiply
hours
now find .......eq.1 => speed
and
.........eq.2 => speed on his return trip
so, in both directions his speed was constant and it was
You can put this solution on YOUR website! A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find his speed?
Let speed be S
Then time on outbound trip =
Time taken on return trip =
Time equation formed:
25 = 30 – S ------- Multiplying by LCD, S
S, or speed = 30 – 25, or mph
