SOLUTION: a jogger ran 3 miles, decrease her speed by 1 mile per hour, and then ran another 4 miles. If her total jogging time was 1.3 hours, find her speed for the first and second part of
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: a jogger ran 3 miles, decrease her speed by 1 mile per hour, and then ran another 4 miles. If her total jogging time was 1.3 hours, find her speed for the first and second part of
Log On
Question 1007607: a jogger ran 3 miles, decrease her speed by 1 mile per hour, and then ran another 4 miles. If her total jogging time was 1.3 hours, find her speed for the first and second part of her run. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! a jogger ran 3 miles, decrease her speed by 1 mile per hour, and then ran another 4 miles. If her total jogging time was 1.3 hours, find her speed for the first and second part of her run.
let x=speed for 1st part of her run
x-1 =speed for 2nd part of her run
travel time=distance/speed
3/x+4/(x-1)=1.3
lcd:x(x-1)
3(x-1)+4x=1.3x^2-1.3x
3x-3+4x=1.3x^2-1.3x
1.3x^2-8.3x+3=0
solve for x by quadratic formula:
a=1.3,b=-8.3c=3c
x=6
x-1=5
speed for 1st part of her run=6 mph
speed for 2nd part of her run=5mph
(