SOLUTION: y=-x^2+4x-10 y= -x^2-6x-4 y= -x^2+10-18 y= 2x^2+4x-3 y= 3x^2-12+8

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: y=-x^2+4x-10 y= -x^2-6x-4 y= -x^2+10-18 y= 2x^2+4x-3 y= 3x^2-12+8      Log On


   

Question 1007559: y=-x^2+4x-10
y= -x^2-6x-4
y= -x^2+10-18
y= 2x^2+4x-3
y= 3x^2-12+8
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You should say what you want to do.