SOLUTION: Given the function f(x)=2e^3x+1 a. Find f(.20) b. Find the value of x such that f(x)=8
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Question 1007538
:
Given the function f(x)=2e^3x+1
a. Find f(.20)
b. Find the value of x such that f(x)=8
Answer by
fractalier(6550)
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Use your calculator to find
f(x) = 2*e^3x + 1
f(.20) = 2*e^(3*.2) + 1 = 4.644
Then set it equal to 8 and solve
8 = 2*e^3x + 1
7 = 2*e^3x
3.5 = e^3x
ln 3.5 = 3x
x = (1/3)ln 3.5 = .418